SOLVED:Prove the formula for the mean of the hypergeometric distribution with the parameters n, a, and N, namely, μ=n ·(a)/(N). [Hint: Make use of the identity ∑r=0^k( m r)( s k-r)=( m s k) which can be obtained by equating the coefficients of x^k in (1 x)^m(1 x)^s and in .(1 x)^m s .]
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